Saturday, August 6, 2011
Is there a chemistry genius out here?
You analyze a sample and determine it contains 13.5g of Ca, 10.8 g O, and .675g H. The molar mass of this hydroxide is 73.07g. Once you have determined the identity of this hydroxide, you decide to react it with .45L Magnesium Nitrate to produce Calcium Nitrate and Magnesium hydroxide. The Ksp of Magnesium Nitrate is 1.17E-5. Magnesium Nitrate is added to 1.4L of 0.35M of your original sample. After the reaction, you measure the solid product and found you created .18 grams of your solid and determine the percent yield of your solid. Since you still have an aqueous product, you decide to react your sample with Copper. You create Calcium and Copper(I) Nitrate. You have some hydrochloric acid lying around so you throw it in with the calcium and produce diatomic Hydrogen and Calcium chloride. You made Hydrogen! You are so excited that you decide to react Hydrogen with Nitrogen to produce ammonia. You know that equilibrium is extremely important for this reaction so you want to make sure you can determine the Keq. Initially, you add 1.84M of diatomic nitrogen to your sample. At equilibrium, the concentration of ammonia is 1.3E-5 M. You increase the pressure of this system to shift equilibrium. You now take the product and react it with water. The Ka of the conjugate acid is 1.75E-5. How many mL of 0.35M of the conjugate base is needed to neutralize 125mL of 2.3M of your acid? What is the geometric shape of the conjugate acid using the principle of VSEPR.
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